1 L 0 02 M Solution Of Conh35so4br Is Mixed With 1l 0 02 M Solution Of Conh35brso4

1 L 0 02 M Solution Of Co Nh3 5so4 Br Is Mixed With 1l 0 02 M 1 l, 0.02 m solution of [co (nh 3) 5 so 4]br is mixed with 1 l, 0.02 m solution of [co (nh 3) 5 br]so 4. the resulting solution is divided into two equal parts (x) and treated with excess of agno 3 solution and bacl 2 solution respectively as shown below: 1 l solution (x) agno 3 solution (excess) → y. 1 l, 0.02 m solution of [co (nh3)5so4]br is mixed with 1l, 0.02 m solution of [co (nh3)5br]so4. the resulting solution is divided into two equal parts (x) and treated with excess agno3 solution and bacl2 solution respectively as shown below.

Solved 1 046 L Of A 0 248mnal Solution Is Mixed With 1 5 L Chegg The first solution is (co(n h3)5so4)br, which contains cobalt in a 3 oxidation state and has a bromide ion as a counter ion. the second solution is (co(n h3)5)so4, which contains cobalt in a 3 oxidation state and has a sulfate ion as a counter ion. Q. 1l,0.02m solution of [c o(n h 3)5s o4]b r is mixed with 1l,0.02m solution of [c o(n h 3)6b r]s o4. the resulting solution is divided into two equal parts (x) and treated with excess of agn o3 solution and b ac l2 solution respectively as shown below:. In an experiment it showed that 10 ml of 0.05m solution of chloride required 10 ml of 0.1m solution of agno3, which of the following will be the formula of the chloride (x stands for the symbol of the element other than chlorine)?. 1 l, 0.02 m solution of [co (nh 3) 5 so 4]br is mixed with 1 l, 0.02 m solution of [co (nh 3) 5 br]so 4. the resulting solution is divided into two equal parts (x) and treated with excess of agno 3 solution and bacl 2 solution respectively as shown below:.

1 L 0 02m Solution Of Co Nh3 5 So4 Br Is Mixed With Ll O 02m Solution In an experiment it showed that 10 ml of 0.05m solution of chloride required 10 ml of 0.1m solution of agno3, which of the following will be the formula of the chloride (x stands for the symbol of the element other than chlorine)?. 1 l, 0.02 m solution of [co (nh 3) 5 so 4]br is mixed with 1 l, 0.02 m solution of [co (nh 3) 5 br]so 4. the resulting solution is divided into two equal parts (x) and treated with excess of agno 3 solution and bacl 2 solution respectively as shown below:. To calculate the concentration of co (n h 3) 5 s o 4]br substitute 0.02 mol for moles of [co (n h 3) 5 s o 4]br and 2l for the volume of the solution. similarly, we can calculate the concentration of (co (n h 3) 5 br)s o 4 by substituting 0.02 mol and 2l of solution. Since the total amount of the mixture is 2 l, when we take 1 l of this mixture, the moles of each complex will be halved: moles of complex 1 in 1 l = 0.02 2 = 0.01 mol. Solution for 1 l,0.02m solution of [co (nh3 )5 so4 ]br is mixed with 1 l, solution is divided into two equal parts (x) and treated with excess agno3 solution and bacl2 solution respectiv. Mixture x=0.02 mol of [co(n h3)5so4]br and 0.02 mol of [co(n h3)5br]so4 was prepared in 2 litre of solution. right on! give the bnat exam to get a 100% scholarship for byjus courses. option (a) is correct. q. mixture x reacts with 0.02 mol of [co(nh3)5so4]br, 0.02 mol of [co(nh3)5br]so4 was prepared in 2 litre of solution.