Factorizing Polynomials A Comprehensive Review Of All Factorization Use suitable identities to find the following products: (i) (x 4)(x 10) (ii) (x 8)(x – 10) (iii) (3x 4)(3x – 5) (iv) (v) (3 – 2x)(3 2x) solution: ( i) (x 4)(x 10): using the identity (x a)(x b). Find the following products using appropriate identities polynomials and factorisation (i) (x 5) (x 5) (ii) (p 3) (p 3) (iii) (y 1) (y 1) ( iv) ( t 2) (t 4) ( v).
Factorise Following Polynomials Using Identities 8a3 B3 6ab 1 Ap state syllabus ap board 9th class maths solutions chapter 2 polynomials and factorisation intext questions and answers. think, discuss and write. which of the following expressions are polynomials ? which are not ? give reasons. [page no. 28] i) 4x 2 5x – 2 is a polynomial. ii) y 2 – 8 is a polynomial. iii) 5 is a constant polynomial. Last updated at dec. 13, 2024 by teachoo. example 16 find the following products using appropriate identities: (x 3) (x 3) (x 3) (x 3) = (x 3)2 using (a b)2 = a2 2ab b2 putting a = x, b = 3 = x2 2 (x) (3) (3)2 = x2 6x 9. davneet singh has done his b.tech from indian institute of technology, kanpur. Use suitable identities to find the following products (i) (x 4)(x 10) (ii) (x 8) (x 10) (iii) (3x 4) (3x – 5) (iv) (y 2 \(\frac { 3 }{ 2 }\)) (y 2 – \(\frac { 3 }{ 2 }\)) (v) (3 – 2x) (3 2x) solution: (i) we have, (x 4) (x 10) using identity, (x a) (x b) = x 2 (a b) x ab. we have, (x 4) (x 10) = x 2 (4 10) x. Ap state syllabus ap board 9th class maths solutions chapter 2 polynomials and factorisation ex 2.5 textbook questions and answers. question 1. use suitable identities to find the following products. question 2. evaluate the following products with¬out actual multiplication. question 3. factorise the following using appro priate identities.
Factorise Following Polynomials Using Identities 8a3 B3 6ab 1 Use suitable identities to find the following products (i) (x 4)(x 10) (ii) (x 8) (x 10) (iii) (3x 4) (3x – 5) (iv) (y 2 \(\frac { 3 }{ 2 }\)) (y 2 – \(\frac { 3 }{ 2 }\)) (v) (3 – 2x) (3 2x) solution: (i) we have, (x 4) (x 10) using identity, (x a) (x b) = x 2 (a b) x ab. we have, (x 4) (x 10) = x 2 (4 10) x. Ap state syllabus ap board 9th class maths solutions chapter 2 polynomials and factorisation ex 2.5 textbook questions and answers. question 1. use suitable identities to find the following products. question 2. evaluate the following products with¬out actual multiplication. question 3. factorise the following using appro priate identities. Use suitable identities to find the following products: (i) (x 4) (x 10) (ii) (x 8) (x 10) (iii) (3x 4) (3x 5) (iv) (y 2 3 2)(y 2 3 2) (v) (3 2x) (3 2x) solution: let's use algebraic identities to proceed with the given problem. (x a)(x b) = x 2 (a b)x ab (a b)(a b) = a 2 b 2 (i) (x 4) (x 10). Here in this exercise, you will use identities involving third degree terms in addition to the identities containing second degree terms. 1. use suitable identities to find the following products: 2. evaluate the following products without multiplying directly: 3. factorise the following using appropriate identities: 4. Concepts covered in mathematics [english] class 9 chapter 2 polynomials are algebraic identities, algebraic identities, polynomials, polynomials in one variable, zeroes of a polynomial, remainder theorem, factorisation of polynomials, factorising the quadratic polynomial (trinomial) of the type ax2 bx c, a ≠ 0., algebraic identities. Ncert solutions for class 9 maths chapter 2 polynomials ex 2.5. ex 2.5 class 9 maths question 1. use suitable identities to find the following products: (i) (x 4)(x 10) (ii) (x 8)(x 10) (iii) (3x 4)(3x 2x) (iv) (\( { y }^{ 2 } \cfrac { 3 }{ 2 }\))( \( { y }^{ 2 } \cfrac { 3 }{ 2 }\)) (v) (3 2x)(3 2x) solution: ex 2.5 class 9 maths question 2.