
Answered Simplify Ab C A C Answer A A Bc O Bartleby If a b c=0 and a^2 b^2 c^2=ab bc ac, then it follows that 0= (a b c)^2=a^2 b^2 c^2 2 (ab bc ac), or a^2 b^2 c^2= 2 (ab bc ac). put this together and we will see that in fact a^2 b^2 c^2=0,. Solve your math problems using our free math solver with step by step solutions. our math solver supports basic math, pre algebra, algebra, trigonometry, calculus and more.

Simplify A B 2a 3b C 2a 3b C Find one factor of the form a^ {k} m, where a^ {k} divides the monomial with the highest power a^ {2} and m divides the constant factor b^ {2} 2bc. one such factor is a b. factor the polynomial by dividing it by this factor. A^2 b^2 c^2 formula is called the sum of squares (of three numbers) formula. it says a^2 b^2 c^2 = (a b c)^2 2ab 2bc 2ca. understand the a^2 b^2 c^2 formula with derivation, examples, and faqs. Answer: (a b) (a b 2c) step by step explanation: the given expression can be factorised as follows: a² b² 2ab 2bc 2ac using the identity (a b)2 = a2 b2 2ab applying formula,we get ⇒ (a b)² 2 (bc ca) looking for common sub expressions : (a b) ⇒ (a b)² 2c (b a) ⇒ (a b) (a b 2c) can't be factorized. On subtracting 2 (ab bc ca) from ab bc ca, we get 3ab 3bc 3ca. ☛ related questions:.

Simplify Ab Bc 2 2ab2c Answer: (a b) (a b 2c) step by step explanation: the given expression can be factorised as follows: a² b² 2ab 2bc 2ac using the identity (a b)2 = a2 b2 2ab applying formula,we get ⇒ (a b)² 2 (bc ca) looking for common sub expressions : (a b) ⇒ (a b)² 2c (b a) ⇒ (a b) (a b 2c) can't be factorized. On subtracting 2 (ab bc ca) from ab bc ca, we get 3ab 3bc 3ca. ☛ related questions:. We have, –ab – bc – ca – 2 (ab bc ca) = –ab – bc – ca – 2ab – 2bc – 2ca on combining the like terms, = –ab – 2ab – bc – 2bc – ca – 2ca = –3ab – 3bc – 3ca. => 2a2 2b2 2c2 – 2ab – 2bc – 2ca = 0 => (a2 – 2ab b2) (b2 – 2bc c2) (c2 – 2ca a2) = 0 => (a –b)2 (b – c)2 (c – a)2 = 0 since the sum of square is zero then each term should be zero => (a –b)2 = 0, (b – c)2 = 0, (c – a)2 = 0 => (a –b) = 0, (b – c) = 0, (c – a) = 0 => a = b, b = c, c = a ∴ a = b = c. Here, we show you a step by step solved example of simplification of algebraic expressions. this solution was automatically generated by our smart calculator: $\frac {x^2 x 2} {x^2 5x 6}$ factor the trinomial $x^2 5x 6$ finding two numbers that multiply to form $6$ and added form $5$.