Solved Let A 1 2 3 A B B 3 4 C B C B 3 2 A 1 And Chegg Question: (1 point) let a= (−2,1,−3),b= (1,3,−6),c= (−2,4,−3), and d= (−5,2,0). find the area of the parallelogram determined by these four points, the area of the triangle abc, and the area of the triangle abd. This is found by first calculating the intersection of b and c, which is {2, 4, 6}, and then finding the common elements between that result and a. hence, the correct option is b: {2}.
Solved 1 Point 1 2 1 2 4 4 Let A 2 1 3 And B 2 2 Chegg Find a × (b ∩ c) b ∩ c = {3, 4} ∩ {"4, 5, 6" } = {"4" } a × (b ∩ c) = {"1, 2, 3" } × {"4" } = {" (1, 4), (2, 4), (3, 4)" } ∩ intersection : common between two sets example 3 let a = {1, 2, 3}, b = {3, 4} and c = {4, 5, 6}. Find step by step solutions and your answer to the following textbook question: let a = {1, 2, 3} and b = {2, 4, 6}. for each relation between a and b given as a subset of a × b, decide whether it is a function mapping a into b. Show that the relation r in the set a = {1, 2, 3, 4, 5} given by r = { (a, b) |a − b| is even} is an equivalence relation. a company has four categories of employees given by assistants (a), clerks (c), managers (m), and an executive officer (e). One to one function: a function f:a → b is one to one if every element of the range b corresponds to exactly one element of the domain a of f. important: for a function f:a → b to be one to one, the range must have more number of elements than the domain.
Solved Problem 4 Let A 1 3 4 B 1 2 5 C 2 4 6 A Chegg Show that the relation r in the set a = {1, 2, 3, 4, 5} given by r = { (a, b) |a − b| is even} is an equivalence relation. a company has four categories of employees given by assistants (a), clerks (c), managers (m), and an executive officer (e). One to one function: a function f:a → b is one to one if every element of the range b corresponds to exactly one element of the domain a of f. important: for a function f:a → b to be one to one, the range must have more number of elements than the domain. Step 1 consider the sets a = {a, b, c} and b = {1, 2, 3} . let n (a) represents the number of elements in the set a and n (b) represents the num. The question asks to find the set of elements { x | x ∈ b or x ∈ c }, which means we are looking for the union of sets b and c. to achieve this, we simply combine all unique elements from both sets b = { 1, 2, 3, 4, 5 } and c = { 1, 3, 5, 7 }. We have found that b ∩c = {2,4} and we also have a = {1,2,3}. now, we look for the intersection of set a and {2,4}, which means finding the elements that are in both sets: (a \cap {2, 4} = {2}. thus, (a \cap (b \cap c) = {2}. therefore, the final answer is {2}. To determine whether the function f is one to one (injective) and onto (surjective), we will analyze the sets a and b, and the function f defined as f= {(1,4),(2,5),(3,6)}.
Solved Let A 1 2 3 4 5 And B 0 3 6 Find A B Chegg Step 1 consider the sets a = {a, b, c} and b = {1, 2, 3} . let n (a) represents the number of elements in the set a and n (b) represents the num. The question asks to find the set of elements { x | x ∈ b or x ∈ c }, which means we are looking for the union of sets b and c. to achieve this, we simply combine all unique elements from both sets b = { 1, 2, 3, 4, 5 } and c = { 1, 3, 5, 7 }. We have found that b ∩c = {2,4} and we also have a = {1,2,3}. now, we look for the intersection of set a and {2,4}, which means finding the elements that are in both sets: (a \cap {2, 4} = {2}. thus, (a \cap (b \cap c) = {2}. therefore, the final answer is {2}. To determine whether the function f is one to one (injective) and onto (surjective), we will analyze the sets a and b, and the function f defined as f= {(1,4),(2,5),(3,6)}.
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