Solved Let 5 2 4 3 6 6 4 5 1 46 4 6 2 4 5 60 4 6 320 一5 6 Chegg Question: let a = 2, 0, 5, b = −2, 6, 3, and c = 2, 3, 4. (a)compute a · b. and. a · b. here’s the best way to solve it. not the question you’re looking for? post any question and get expert help quickly. The question asks to find the set of elements { x | x ∈ b or x ∈ c }, which means we are looking for the union of sets b and c. to achieve this, we simply combine all unique elements from both sets b = { 1, 2, 3, 4, 5 } and c = { 1, 3, 5, 7 }.
Solved 3 Let A 1 2 3 4 5 6 And 1 2 3 4 5 6 P1 Chegg For example, if you think of set a as even numbers from 0 to 10, set b as all single digit numbers including 0, and set c as numbers from 4 to 10 including 5 and 6, you can visualize how these numbers interact with each other in terms of intersections and unions. Now that you know the core techniques, let’s look at how they work in real problems. these examples mix steps like distributing, factoring, reducing, and combining like terms — because in actual math class, you don’t get one skill at a time. Calculation: given that: a = {1, 2, 3}, b = {3, 4} and c = {4, 5, 6} ⇒ b ∩ c = {4} ⇒ a ∪ (b ∩ c) = {1, 2, 3} ∪ {4} ⇒ a ∪ (b ∩ c) = {1, 2, 3, 4}. hence, option 4 is correct. Free equation solver helps you to calculate linear, quadratic and polynomial systems of equations. answers, graphs, roots, alternate forms.
Solved Let A 1 3 2 0 2 0 2 6 5 2 4 3 0 0 5 10 0 15 Chegg Calculation: given that: a = {1, 2, 3}, b = {3, 4} and c = {4, 5, 6} ⇒ b ∩ c = {4} ⇒ a ∪ (b ∩ c) = {1, 2, 3} ∪ {4} ⇒ a ∪ (b ∩ c) = {1, 2, 3, 4}. hence, option 4 is correct. Free equation solver helps you to calculate linear, quadratic and polynomial systems of equations. answers, graphs, roots, alternate forms. Find a × (b ∩ c) b ∩ c = {3, 4} ∩ {"4, 5, 6" } = {"4" } a × (b ∩ c) = {"1, 2, 3" } × {"4" } = {" (1, 4), (2, 4), (3, 4)" } ∩ intersection : common between two sets example 3 let a = {1, 2, 3}, b = {3, 4} and c = {4, 5, 6}. Video answer: x belongs to a bar b, that's what it's said in the question. the meaning is that x is in a and x is not in b, and they have given the second subdivision as a like this. However, this includes each handshake twice (1 with 2, 2 with 1, 1 with 3, 3 with 1, 2 with 3 and 3 with 2) and since the orginal question wants to know how many different handshakes are possible we must divide by 2 to get the correct answer. Your solution’s ready to go! our expert help has broken down your problem into an easy to learn solution you can count on. see answer question: 6. let s = { (2,0,7), (2,4,5), (2, 12,13). if possible, write x = (2,20, 3) as a linear combination of the vectors in s.
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