The Speed Of A Swimmer Is 4 Km H 1 In Still Water If The Swimmer
The Speed Of A Swimmer Is 4 Km H 1 In Still Water If The Swimmer A swimmer swims perpendicular to river flow and reaches point b. if velocity of swimmer in still water is 4 km h, asked feb 7, 2023 in physics by lakshdave ( 57.1k points). Given v bg β = 4 kmph. time taken to cross the river is t = 1 km 4 kmh 1 = 1 4 hr. drift d = v river Γ t = 3 4 k m. β΄ v = 3 km hr.
The Speed Of A Swimmer Is 4 Km H 1 In Still Water If The Swimmer
The Speed Of A Swimmer Is 4 Km H 1 In Still Water If The Swimmer The speed of a swimmer is 4kmh^( 1) in still water. if the swimmer makes his strokes normal to the flow of river of width 1 km, he reaches a point 750 m down the stream on the opposite bank. the speed of the river water is kmh^( 1) single digit integer ( 9 to 9) type your answer here 1 2 3 4 5 6. 7 8 9 x. The speed of a swimmer is 4kmh^ ( 1) in still water.if the swimmer makes his strokes normal to the flow of river of width 1km,he reaches a point 750m down the stream on the opposite bank. The speed of a swimmer is $$4 \mathrm{~km} \mathrm{~h}^{ 1}$$ in still water. if the swimmer makes his strokes normal to the flow of river of width $$1 \mathrm{~km}$$, he reaches a point $$750 \mathrm{~m}$$ down the stream on the opposite bank. $t = \dfrac{{1km}}{{4km{h^{ 1}}}} = \dfrac{1}{4}hr = 0.25hr$ since the river flows with a velocity $(v')$ of $3km{h^{ 1}}$ and the man would also move along the direction of the flow of the river due to the speed of the river, given he would swim in the river for $0.25hr$.
A Swimmer Can Swim With Velocity Of 12 Km H In Still Water Water
A Swimmer Can Swim With Velocity Of 12 Km H In Still Water Water The speed of a swimmer is $$4 \mathrm{~km} \mathrm{~h}^{ 1}$$ in still water. if the swimmer makes his strokes normal to the flow of river of width $$1 \mathrm{~km}$$, he reaches a point $$750 \mathrm{~m}$$ down the stream on the opposite bank. $t = \dfrac{{1km}}{{4km{h^{ 1}}}} = \dfrac{1}{4}hr = 0.25hr$ since the river flows with a velocity $(v')$ of $3km{h^{ 1}}$ and the man would also move along the direction of the flow of the river due to the speed of the river, given he would swim in the river for $0.25hr$. If the swimmer makes his strokes normal to the flow of river of width 1 km, he reaches a point 750 m down the stream on the opposite bank. the speed of the river water is km h 1 q. Speed of the man = 4 km h. width of the river = 1 km. time taken to cross the river t = width of the river speed of the man. t=1 4hr =60 4min=15 min. step 3: final distance along the river. as the man makes his strokes normal to the river current. so, distance covered along the river = speed of river Γ taken by the man to reach other bank =3. From the geometry, we have: \[ x = 750 \, \text{m} = 0.75 \, \text{km} \] substituting \( x = 750 \, \text{m} \) and the speed of the swimmer \( v s = 4 \, \text{km h} \), we can find \( v m \): \[ x = \frac{v m}{4} \times t \] thus, \[ v m = 3 \, \text{km h} \]. The speed of the swimmer in still water is given as 4 km h, and the width of the river is 1 km, which can be converted to meters: 1 km = 1000 m. the swimmer ends up 750 m downstream on the opposite bank of the river.
Answered Speed Of Water In A River Is 4 Km H And Man Can Swim At 5 Km
Answered Speed Of Water In A River Is 4 Km H And Man Can Swim At 5 Km If the swimmer makes his strokes normal to the flow of river of width 1 km, he reaches a point 750 m down the stream on the opposite bank. the speed of the river water is km h 1 q. Speed of the man = 4 km h. width of the river = 1 km. time taken to cross the river t = width of the river speed of the man. t=1 4hr =60 4min=15 min. step 3: final distance along the river. as the man makes his strokes normal to the river current. so, distance covered along the river = speed of river Γ taken by the man to reach other bank =3. From the geometry, we have: \[ x = 750 \, \text{m} = 0.75 \, \text{km} \] substituting \( x = 750 \, \text{m} \) and the speed of the swimmer \( v s = 4 \, \text{km h} \), we can find \( v m \): \[ x = \frac{v m}{4} \times t \] thus, \[ v m = 3 \, \text{km h} \]. The speed of the swimmer in still water is given as 4 km h, and the width of the river is 1 km, which can be converted to meters: 1 km = 1000 m. the swimmer ends up 750 m downstream on the opposite bank of the river.
A Swimmer Can Swim With Velocity Of 12 Km H In Still Water Water
A Swimmer Can Swim With Velocity Of 12 Km H In Still Water Water From the geometry, we have: \[ x = 750 \, \text{m} = 0.75 \, \text{km} \] substituting \( x = 750 \, \text{m} \) and the speed of the swimmer \( v s = 4 \, \text{km h} \), we can find \( v m \): \[ x = \frac{v m}{4} \times t \] thus, \[ v m = 3 \, \text{km h} \]. The speed of the swimmer in still water is given as 4 km h, and the width of the river is 1 km, which can be converted to meters: 1 km = 1000 m. the swimmer ends up 750 m downstream on the opposite bank of the river.
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